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Home/ Questions/Q 8331479
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T02:25:40+00:00 2026-06-09T02:25:40+00:00

I’m not even sure I’m asking or going about this the right way but

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I’m not even sure I’m asking or going about this the right way but it’s probably easier if I just show it. Basically, I’m trying to have run an attr of each div as a parameter through a function and have it return a different result based on that div’s attr.

The example, as you can see, is a group of dropdowns that appear when you click on a link in the container div. If you make a selection it saves that as a attr in the parent div. The problem arises when you click out, then back in on the container … instead of reshowing each dropdown with the appropriate default or selection showing, it just mirrors the result of the a next to it.

http://jsfiddle.net/nosfan1019/b7F6x/5/

TIA

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T02:25:41+00:00Added an answer on June 9, 2026 at 2:25 am

    foo = foo.find('.dropdown-toggle').html(_new + '<b class="caret"></b>');

    with this line you get two divs and hence you’ve change both values(in case the value was chosen from the droplist).

    To restore selected values correctly:

    function modified(_select) {
        console.log("modify");
        foo = $('#box').html();
        foo = $(_select).html(foo);
        // iterate on collection to restore selected value from selection tag;
        foo.filter("div[selection]").each(function(i, v){
            var selected = $(v).attr('selection');
            $(v).find('.dropdown-toggle').html(selected + '<b class="caret"></b>');                
        });                
    }
    

    Then, it’s needed to be checked if any of parentDiv has [selection] attr:

    if($(y).filter("div[selection]").length > 0){
        return modified(y);
    }         
    

    http://jsfiddle.net/b7F6x/50/

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