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Home/ Questions/Q 8320825
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T22:47:42+00:00 2026-06-08T22:47:42+00:00

I’m running a PHP script every night using a cron service. Everything it outputs

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I’m running a PHP script every night using a cron service. Everything it outputs will be printed to an log file for debug prepossess. The file I use will retrieve xml’s from a different site using the function ‘file_get_contents()’. But the function can return an error which I really don’t want to see as I am already showing a custom error.

Quick example of my piece of code:

$buffer = @file_get_contents('http://xx:xx@xx/xml/xx?offset=2') or print('retry in 5 seconds');

if($buffer === false) {
  sleep(5);
  $buffer = @file_get_contents('http://xx:xx@xx/xml/xx?offset=2') or print('error notice');
}

The problem is the first one will trigger an error and print it’ll retry in 5 seconds. How can I correctly suppress the thrown error?

I have an error handler, but I prefer not to catch this error separately.

Edited:
My solution wasn’t to change the error_reporting, but to catch the error message. If it starts with ‘file_get_contents()’, no error will be thrown. This is not the best way, but will do the job for me.

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  1. Editorial Team
    Editorial Team
    2026-06-08T22:47:44+00:00Added an answer on June 8, 2026 at 10:47 pm

    You can try inserting this at the start:

    error_reporting(0);
    

    Then after the code with the error/warning:

    error_reporting(E_ALL ^ E_WARNING);
    
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