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Home/ Questions/Q 8250761
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T00:00:32+00:00 2026-06-08T00:00:32+00:00

I’m super new to C# and this is my third question here regarding it.

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I’m super new to C# and this is my third question here regarding it.

I’m making an app which can be minimized to the system tray. I have two forms named Form1 and Form2. What I have done so far is:

In Form1, I have a button which is showing the Form2 using this code:

this.Hide();
Form2 form2 = new Form2();
form2.Show();

The Form2 has a button which is hiding it, using this code:

this.Hide();

Now, I have the tray icon on the task bar. The tray icon has a ContexMenuStrip, and there is an option named show using this code:

Form1 form1 = new Form1();
form1.Show();

The problem is that when I click on it, a second tray icon is appearing on the taskbar. Both tray icons have the same menu and both are working. If I click on show again another window with Form1 pops up, and there are three tray icons, and so on….

Can someone help me?

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  1. Editorial Team
    Editorial Team
    2026-06-08T00:00:35+00:00Added an answer on June 8, 2026 at 12:00 am

    It’s because you are creating a new Form1 everytime.

    Form1 form1 = new Form1();
    

    You don’t want to create a new Form1, you want to show the old one. Give Form2 a reference to your first form1 (call it theMainform1 for example). And then instead of

    Form1 form1 = new Form1();
    form1.Show();
    

    You want to do

    theMainform1.Show();
    

    So you would have:

     this.Hide();
     Form2 form2 = new Form2();
     form2.theMainform1 = this;
     form2.Show();
    
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