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Home/ Questions/Q 6022011
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T03:47:49+00:00 2026-05-23T03:47:49+00:00

I’m trying create this function such that if any key besides any of the

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I’m trying create this function such that if any key besides any of the arrow keys are pressed, the loop continues until an arrow key is pressed. The program crashes every time and doesn’t display the error. Any idea why?

def speed(self, key):
    # Figure out if it was an arrow key. If so
    # adjust speed

    n = 'go'
    while n == 'go':
        if key == pygame.K_LEFT:
            x_speed=-5
            y_speed=0
            return x_speed, y_speed
            n = 'stop'
        if key == pygame.K_RIGHT:
            x_speed = 5
            y_speed = 0
            return x_speed, y_speed
            n = 'stop'
        if key == pygame.K_UP:
            y_speed = -5
            x_speed = 0
            return x_speed, y_speed
            n = 'stop'
        if key == pygame.K_DOWN:
            y_speed = 5
            x_speed = 0
            return x_speed, y_speed
            n = 'stop'
        else:
            continue
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  1. Editorial Team
    Editorial Team
    2026-05-23T03:47:50+00:00Added an answer on May 23, 2026 at 3:47 am

    Observing the following criteria:

    • The loop will only end when key is an arrow, because the only return statements and n = 'stop' statements happen when key is an arrow key.

    • The value of key will never change from inside the loop, because the only declaration of key is in the definition of speed()

    We determine: if we call speed() with a non-arrow key, the loop will never finish. When you hit an infinite loop in the main execution thread of a program, it has a habit of freezing everything and eating delicious CPU cycles.

    The solution is to implement your logic asynchronously. If you press a key, it should observe the state of the system, change whatever it needs to trigger actions, then quickly return so as to not slow the program. A never-ending while loop isn’t anything close to optimal in the middle of your key-detection logic.

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