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Home/ Questions/Q 910603
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T17:04:15+00:00 2026-05-15T17:04:15+00:00

I’m trying to dynamically create a div to show error messages using jquery. I’m

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I’m trying to dynamically create a div to show error messages using jquery. I’m able to use append() to create the HTML easily enough, but I need to call a php variable in order to display the content. If I just try adding php opening and closing tags like I would ordinarily, the append method doesn’t behave as expected and outputs a seemingly random section from the middle of the line.
How can I overcome this problem?

Here’s the jquery code as I have it:

$(document).ready(function() {
    var errors_php = "<?php  echo validation_errors('<li>','</li>'); ?>";
    $('#wrapper').append("<div id='errors'><ul>"+errors_php+"</ul></div>");
    $('#errors').slideDown('slow');
});

Note: the validation_errors() function is a codeigniter method. Incidentally, if I remove the errors_php variable from the append() it works as expected, displaying an empty div.

EDIT:

The generated code is:

<div id="errors"><ul>',''); ?&gt;</ul></div>
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  1. Editorial Team
    Editorial Team
    2026-05-15T17:04:16+00:00Added an answer on May 15, 2026 at 5:04 pm

    As per your comment:

    I just looked up that question and it
    is exactly what I’m trying to do.
    Unfortunately, I don’t understand from
    the answers how they’ve solved it.
    I’ve never used json data before.
    Where should I put that piece of code?

    JSON data is simply JavaScript Object Notation, so if you set a JavaScript a variable to a JSON value it will essentially recreate a copy of the object that was serialized into JSON in the first place.

    var errors_php = "<?php  echo validation_errors('<li>','</li>'); ?>";
    

    should be:

    var errors_php = <?php echo json_encode(validation_errors('<li>','</li>')); ?>;
    
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