Question

I’m trying to find a word and replace it with a link. So for example:

<root>
<description>
Uniquely cultivate optimal supply chains before multidisciplinary infrastructures.
</description>
</root>

In the xsl, I’m trying to search a particular word and replace that word with a link. For example I want to replace the word “cultivate” with cultivate so the final output on the page will be:

 Uniquely <a href="http://google.com">cultivate</a> optimal supply chains before multidisciplinary infrastructures. 

I’m approaching this problem using replace function like:

<xsl:variable name="description" select="description" />

and then

 replace($description, "(.*)(cultivate.*)", "$1test$2")

This just adds the word test before cultivate. I would really appreciate any help.

–UPDATE–
I was able to fix this issue using replace like this

<xsl:variable name="description" select="description" />
Description: <xsl:value-of disable-output-escaping="yes" select="replace($description, '(.*)(cultivate)(.*)', '$1&lt;a href=http://google.com &gt;cultivate&lt;/a&gt;$3')" />

Answer 1

Use analyze-string http://www.w3.org/TR/xslt20/#regex-examples e.g.

<xsl:template match="description">
  <xsl:analyze-string select="." regex="cultivate">
    <xsl:matching-substring>
      <a href="http://example.com">
        <xsl:value-of select="."/>
      </a>
   </xsl:matching-substring>
   <xsl:non-matching-substring>
     <xsl:value-of select="."/>
   </xsl:non-matching-substring>
 </xsl:analyze-string>
</xsl:template>