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Home/ Questions/Q 8318847
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T22:07:19+00:00 2026-06-08T22:07:19+00:00

I’m trying to get photos through the facebook Graph API. Here’s my code: function

  • 0

I’m trying to get photos through the facebook Graph API. Here’s my code:

function getImgURL(photos, m) {
  n=0;
  while (typeof photos[n] !== 'undefined') {
    photourl[m] = photos[n].images[2].source;
    n++;
    m++;
  }
}

$('document').ready(function() {
  var url = "https://graph.facebook.com/179877662120200";
  var json = $.ajax(url);
  console.log(json);
  console.log(json.responseText);
  var photos = $.parseJSON(json);
  console.log(photos);
  console.log(photos);
  var m = 0;
  getImgURL(photos, m);
  while (typeof photos.paging !== 'undefined') {
    json = $.ajax(photos.paging.next);
    photos = $.parseJSON(json);
    getImgURL (photos, m);
  }
});

So looking at the log, it returns the variable json as an object. One property of the object is “responseText” but when I try to print that to the console it returns “undefined”

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T22:07:20+00:00Added an answer on June 8, 2026 at 10:07 pm

    AJAX/JSON-P requests are (usually – always in the case of JSON-P) asynchronous operations – you need to receive and handle the response in a callback, not straight after the request.

    The object you think you’re getting is actually a deferred object generated by jQuery, not the response.

    So:

    $.getJSON(url).done(function(response) {
        console.log(response); //here's your response
    });
    

    Or, if you’d rather declare the callback later on for any reason:

    var req = $.getJSON(url);
    //other, synchronous code here
    req.done(function(response) { console.log(response); });
    

    Some other points:

    1) jQuery automatically parses JSON strings returned as part of JSON-P requests, so you don’t need to parse it yourself as you currently are

    2) your n var is (seemingly) global

    3) you might want to improve your indentation as the code isn’t super readable

    4) your loop can be simplified to while(photos[n]) {...

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