Question

I’m trying to pass a date to a function that calculates the age of a person. However, the date is in Y-m-d format in the database, and I need to pass it in “Y-m-d” format. I have tried string concatenation, but that failed, maybe because it just operated the numbers using minus(-) operator. Kindly let me know how to do the same.

I am fetching the DOB in $dob variable, and passing it to CalculateAge($dateofbirth) function

Here is the code:

function CalculateAge($BirthDate)
{
        // Put the year, month and day in separate variables
        list($Year, $Month, $Day) = explode("-", $BirthDate);

    //echo $Year;       

        $YearDiff = date("Y") - $Year;
        // If the birthday hasn't arrived yet this year, the person is one year younger
        if(date("m") < $Month || (date("m") == $Month && date("d") < $Day))
        {
                $YearDiff--;
        }
    if(date("m") > $Month || date("m") == $Month)
        $MonthDiff = date("m") - $Month;
    else
        $MonthDiff = 12 - $Month + date("m");

    $age = $YearDiff + $MonthDiff/12;
        return $age;
}
$dob = mysql_query("SELECT date_of_birth FROM kids_informations WHERE user_id = '$usid'");  
$rs = CalculateAge($dob);   

Answer 1

This would probably work –

$result = mysql_query("SELECT date_of_birth FROM kids_informations WHERE user_id = '$usid'");  

while($row = mysql_fetch_array($result))
{
   $dob = $row['date_of_birth'];
}

$dob = "\"".$dob."\"";

$rs = CalculateAge($dob);