Question

Im trying to pass an array that I already found by a query into another query. For example:

$first_query = "SELECT id FROM from Table WHERE user = '{$_SESSION['id'}'";
$result = mysql_query($first_query,$connection);
$ids = mysql_fetch_array($result);

This is where it gets tricky for me. I want to pass $ids into the next query.

$id_implode = implode(", ", $ids)
$second_query = "SELECT * FROM Table2 WHERE id = '{$id_implode}';

The second query doesnt seem to be working. Any help is greatly appreciated!

Answer 1

your second query’s syntax is wrong. Once evaluated it should read

select * from Table2 where id in (1,2,3)

ditch the curly braces and change the = to in. Don’t use OR – that’s a dumb way of ignoring good sql functionality

EDIT: Teneff’s comment makes a very good point – why are you approaching the problem in this way? If there is a relationship between the tables they can be joined and all the data you want can be retrieved in a single query. If for some reason you can’t / won’t join the tables you could at least try a sub-query

select * from table2 where id in (select id from table where user = $_SESSION['id']);