Question

I’m trying to set up a “close to start” button in a game. The game takes the user from view to view like a maze. The user could be on any view, but I want a way to get them back to the start screen. Is there a way to find and return the ID of the current view for my findViewByID? I’ve found a I’ve tried the following code in various forms:

OnClickListener closetomain = new OnClickListener() {
@Override
public void onClick(View v) {

     int currentid = v.findFocus().getId();

     RelativeLayout hideme = (RelativeLayout)findViewById(currentid);
     hideme.setVisibility(View.GONE);
     setContentView(R.layout.main);
//         RelativeLayout showme = (RelativeLayout)findViewById(R.id.startLayout);
//         showme.setVisibility(View.VISIBLE);
    }
};

Answer 1

Okay, it turns out I should have given each close button the same ID and used theisenp’s suggestion for the simplest code (well, that I could understand). It also turns out that I should have started by putting each level/layout in its own activity. You live and you learn I guess. Below is my XML and java. It may not be the elegant solution but I’m not sure I care all that much as long as it works.

        <ImageButton android:id="@+id/closeButton"
    android:layout_height="wrap_content" 
    android:background="@drawable/close" 
    android:layout_width="wrap_content" 
    android:layout_alignParentBottom="true"
    android:layout_marginLeft="10dp"
    android:layout_marginBottom="10dp"
    android:onClick="closetomain">
    </ImageButton>

And here’s my Java:

public void closetomain(View view) {
switch(view.getId()) {
    case R.id.closeButton:
        setContentView(R.layout.main);
        break;
    }
}