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Home/ Questions/Q 8349735
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T08:05:58+00:00 2026-06-09T08:05:58+00:00

I’m trying to use a Java library (JOhm) with Scala and noticed it fails

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I’m trying to use a Java library (JOhm) with Scala and noticed it fails when the lib tries to read the fields of my Scala classes with something like model.getClass().getDeclaredFields().

Then I decided to try to do the same with simple examples in the Scala interpreter:

scala> import java.lang.reflect.Field;
import java.lang.reflect.Field

scala> class myClass(attribute1: String, attribute2: String, attribute3: String)
defined class myClass

scala> val myInstance = new myClass("value1", "value2", "value3")
myInstance: myClass = myClass@7055c39a

scala> myInstance.getClass().getDeclaredFields()
res0: Array[java.lang.reflect.Field] = Array()

Indeed, we get no field at all.

Now, what if I try this:

scala> class myClass2(attribute1: String, attribute2: String, attribute3: String) { override def toString = this.attribute1 }
defined class myClass2

scala> val myInstance2 = new myClass2("value1", "value2", "value3")
myInstance2: myClass2 = value1

scala> myInstance2.getClass().getDeclaredFields()
res1: Array[java.lang.reflect.Field] = Array(private final java.lang.String myClass2.attribute1)

So if use one of the fields in one of the class’ methods, it is found by getDeclaredFields(). What am I missing here?

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  1. Editorial Team
    Editorial Team
    2026-06-09T08:06:00+00:00Added an answer on June 9, 2026 at 8:06 am

    What you are missing is that constructor parameters are not automatically promoted to fields.

    Rather, they are promoted only if they are used. You used attribute1 so it was turned into a field; you didn’t use the others so they were not.

    If you declare them as val or var, or the class is a case class, they will also be promoted to fields (since they will actually have accessor methods generated, and thus are used).

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