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Home/ Questions/Q 7715567
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T02:25:07+00:00 2026-06-01T02:25:07+00:00

I’m unsure how to do this. One way is: import urllib.request; urllib.request.urlretrieve(‘www.example.com/file.tar’, ‘file.tar’) Another

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I’m unsure how to do this. One way is:

import urllib.request;
urllib.request.urlretrieve('www.example.com/file.tar', 'file.tar')

Another way would be:

import urllib.request;

#Set as appropriate
userAgent = ....;

req = urllib.request.Request('www.example.com/file.tar', headers={'User-Agent' : userAgent});
response = urllib.request.urlopen(req);

#Save the file
f = open('file.tar', 'wb');
f.write(response.read());
f.close()

I’m not sure which method to use. I’ll be downloading many files (with a pattern filename) in a loop. However, I would like to be able to set up a user-agent header. It’s not critical but I’d like to.

EDIT: I forgot to mention that I prefer the first method but I don’t know how to set the user-agent header with urlretrieve.

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  1. Editorial Team
    Editorial Team
    2026-06-01T02:25:08+00:00Added an answer on June 1, 2026 at 2:25 am

    I am moving what started as comments, to an answer…

    Your second example is pretty much doing what it needs to, in making a request object with a custom header and then reading the results into a local file.

    urlretrieve is a higher level function so it only does exactly what the docs say: Downloads a network resource to a local file and tells you where the file is. If you don’t like the slightly lower level approach of your second example and you want more higher-level functionality, you can look into using the Requests library

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