Question

I`m using this “plugin” found on web to preview some images in a php/linux website.

<script type="text/javascript">
function pimg()
{
    this.xOffset = 5;
    this.yOffset = 50;
    $("a.pimg").hover(function (e)
    {
        this.img_title = this.title;
        this.title = "";
        var img_src = $(this).attr('img_src');
        var desc = (this.img_title != "") ? "<h3>" + this.img_title + "</h3>" : "";
        var image = (img_src) ? img_src : this.src;
        $("body").append("<div id='pimg'><img src='" + image + "' alt='Image preview' />" + desc + "</div>");
        $("#pimg").css("top", (e.pageY - xOffset) + "px").css("left", (e.pageX + yOffset) + "px");
        $("#pimg").fadeIn(700);
    }, function ()
    {
        this.title = this.img_title;
        $("#pimg").remove();
    });
    $("a.pimg").mousemove(function (e)
    {
        $("#pimg").css("top", (e.pageY - xOffset) + "px").css("left", (e.pageX + yOffset) + "px");
    });
};
$(document).ready(function($){
    pimg();
}) 
</script>

<div class="images">
                  <a href="#" img_src='<?=TF?>/img/design/testimonials/Tuscg.png' class="pimg">View Testimonial</a>
            </div>

What I want is to make the image preview to appear inside the visible browser window and not create new space for it ( in cases like the link is in the right bottom of the browser window ). I know I have to play with the positioning, but how can do it dinamically so that the image will appear only in the current viewable content of the browser window.

Thanks!

Answer 1

Your code is fine. You just need to add this to your CSS styles (DEMO)

#pimg{position:absolute;display:none;}

Aside from that, you’ll just need to modify this code to the correct x/y coordinates you desire.

$("#pimg").css("top", (e.pageY - xOffset) + "px").css("left", (e.pageX + yOffset) + "px");