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Home/ Questions/Q 974921
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T03:30:20+00:00 2026-05-16T03:30:20+00:00

import java.lang.Process; import java.io.*; import java.io.InputStream; import java.io.IOException; public class prgms{ public static void

  • 0
  import java.lang.Process;    
  import java.io.*;   
  import java.io.InputStream;    
  import java.io.IOException;    
  public class prgms{    
  public static void main(String[] args) {    
    try {    
      // Execute a command without arguments    
      String command = "java JavaSimpleDateFormatExample";    
      Process child = Runtime.getRuntime().exec(command);    

      // Execute a command with an argument    
      // command = "java JavaStringBufferAppendExample";    
     //child = Runtime.getRuntime().exec(command);    
    } catch (IOException e) {    
    }    
    InputStream in = child.getInputStream();    
    int c;    
    while ((c = in.read()) != -1) {    
        process((char)c);    
    }    
    in.close();    
  }    
}    

I have modified this way… but the following error occurs,

prgms.java:17: cannot find symbol    
symbol  : variable child    
location: class prgms     
InputStream in = child.getInputStream();    
                 ^
prgms.java:20: cannot find symbol    
symbol  : method process(char)    
location: class prgms    
        process((char)c);    
        ^    
2 errors   
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T03:30:20+00:00Added an answer on May 16, 2026 at 3:30 am

    You’re indeed ignoring the stdout and stderr streams of the Process returned by Runtime#exec().

    This is going to be a long story, so here’s just a link: When Runtime.exec won’t. Read all the four pages.

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