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Home/ Questions/Q 4233000
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T02:09:58+00:00 2026-05-21T02:09:58+00:00

In C# 4.0, I have a standard object, called Customer It has properties and

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In C# 4.0, I have a standard object, called “Customer” It has properties and a public empty constructor.

I need to serialize a generic List<Customer> to XML so I can save it, then load it up and deserialize it back.

Is there now framework support for this that is simpler than it was in .NET 2.0 ?

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  1. Editorial Team
    Editorial Team
    2026-05-21T02:09:59+00:00Added an answer on May 21, 2026 at 2:09 am

    Here’s what I use in my library of goodies:

    public static string SerializeAsXml<TSource>(object element) where TSource : new()
    {
        return SerializeAsXml<TSource>(element, new Type[] {});
    }
    
    public static string SerializeAsXml<TSource>(object element, Type[] extraTypes) where TSource : new()
    {
        var serializer = new XmlSerializer(typeof(TSource), extraTypes);
        var output = new StringBuilder();
        using (StringWriter writer = new XmlStringWriter(output))
        {
            serializer.Serialize(writer, element);
        }
        return output.ToString();
    }
    
    public static TDestination Deserialize<TDestination>(string xmlPath) where TDestination : new()
    {
        return Deserialize<TDestination>(xmlPath, new Type[] { });
    }
    
    public static TDestination Deserialize<TDestination>(string xmlPath, Type[] extraTypes) where TDestination : new()
    {
        using (var fs = new FileStream(xmlPath, FileMode.Open))
        {
            var reader = XmlReader.Create(fs);
            var serializer = new XmlSerializer(typeof(TDestination), extraTypes);
            if (serializer.CanDeserialize(reader))
            {
                return (TDestination)serializer.Deserialize(reader);
            }
        }
        return default(TDestination);
    }
    

    Not super simple, but it works. Note this deserializes from a path only, but you could easily change it to deserialize from a string, just strip out the FileStream.

    The XmlStringWriter looks like:

    public class XmlStringWriter : StringWriter
    {
    
        public XmlStringWriter(StringBuilder builder)
            : base(builder)
        {
    
        }
    
        public override Encoding Encoding
        {
            get { return Encoding.UTF8; }
        }
    
    }
    

    I’m simply forcing UTF8 encoding on the XML output.

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