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Editorial Team
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Asked: 2026-05-24T12:08:39+00:00

In form.php <html> <body> <form action=process.php method=post> <input type=text name=dat /> <input type=submit value=submit

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In “form.php”

<html>
    <body>
        <form action="process.php" method="post">
            <input type="text" name="dat" />
            <input type="submit" value="submit" />
        </form>
    </body>
</html>

In “process.php”:

<?php
    echo $_POST['dat'];

    mysql_connect("localhost", "root", "123456")
            or die("can't connect");
    mysql_select_db("st")
        or die("can't selectdb");

    $query = "INSERT INTO sts (time) VALUES ( " . $_POST['dat']. "  ) ";


    $result = mysql_query($query)
        or die(mysql_error());

    $mysql_close();

?>

This give me 0000-00-00 in the database, in the field name “time” of type “DATE”.
If using this:

$time = explode("-", $_POST['dat']);
    $query = "INSERT INTO sts (time) VALUES ( " .  date("m-d-Y", mktime(0, 0, 0, $time[1], $time[2], $time[0])). "  ) ";

-> doesn’t work either

EDIT:
I’ve changed from “m-d-Y” to “Y-m-d” for appropriate semantic, but it still doesn’t work

However, if I change the code like this:

$query = "INSERT INTO sts (time) VALUES ('1991-10-05') ";

it works.

Can anyone explain this for me?

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1 Answer

  1. Editorial Team

    Neither if your two PHP examples have the date being quoted. They’ll generate queries that look like:

    INSERT INTO sts (time) VALUES (2009-01-02);

    which will be parsed down to

    INSERT INTO sts (time) VALUES (2006)

    2009-01-02 is a numeric literal with two subtractions, NOT a date. To get get MySQL to treat this as a date value, it MUST be quoted:

    INSERT INTO sts (time) VALUES ('2009-01-02');
                               ^----------^--- quotes MUST be present

    So your PHP should look like:

    $date = mysql_real_escape_string($_POST['dat']);

$query = "INSERT INTO sts (time) VALUES ('$dat');";
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