In my MySQL table I’ve created an ID column which I’m hoping to auto-increment in order for it to be the primary key.
I’ve created my table:
CREATE TABLE `test` (
`id` INT( 11 ) NOT NULL AUTO_INCREMENT PRIMARY KEY ,
`name` VARCHAR( 50 ) NOT NULL ,
`date_modified` DATETIME NOT NULL ,
UNIQUE (
`name`
)
) TYPE = INNODB;
then Inserted my records:
INSERT INTO `test` ( `id` , `name` , `date_modified` )
VALUES (
NULL , 'TIM', '2011-11-16 12:36:30'
), (
NULL , 'FRED', '2011-11-16 12:36:30'
);
I’m expecting that my ID’s for the above are 1 and 2 (respectively). And so far this is true.
However when I do something like this:
insert into test (name) values ('FRED')
on duplicate key update date_modified=now();
then insert a new record, I’m expecting it to be 3, however now I’m shown an ID of 4; skipping the place spot for 3.
Normally this wouldn’t be an issue but I’m using millions of records which have thousands of updates every day.. and I don’t really want to even have to think about running out of ID’s simply because I’m skipping a ton of numbers..
Anyclue to why this is happening?
MySQL version: 5.1.44
Thank you
Is it possible to change your key to unsigned bigint – 18,446,744,073,709,551,615 is a lot of records – thus delaying the running out of ID’s
Found this in mysql manual http://dev.mysql.com/doc/refman/5.1/en/example-auto-increment.html
More reading here http://dev.mysql.com/doc/refman/5.6/en/information-functions.html#function_last-insert-id it could be inferred that the insert to a transactional table is a rollback so the manual says “LAST_INSERT_ID() is not restored to that before the transaction”
What about for a possible solution to use a table to generate the ID’s and then insert into your main table as the PK using LAST_INSERT_ID();
From the manual: