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Home/ Questions/Q 8368797
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T13:28:25+00:00 2026-06-09T13:28:25+00:00

In mysql I have this code below: $row = mysql_fetch_assoc($query); $dbactive = $row[‘active’]; if

  • 0

In mysql I have this code below:

$row = mysql_fetch_assoc($query);
$dbactive = $row['active'];

if ($dbactive == 1){

...

}...

But I have to use mysqli in my project. So I have tried changing it below but I am not quite getting it right. Can anyone just help me correct the below statement in mysqli so it matches the mysql’s statement above?

UPDATE:

My attempt in mysqli:

   // don't use $mysqli->prepare here
        $query = "SELECT TeacherForename, TeacherSurname, TeacherUsername, TeacherPassword, Active FROM Teacher WHERE TeacherUsername = ? AND TeacherPassword = ? LIMIT 1";
        // prepare query
        $stmt=$mysqli->prepare($query);
        // You only need to call bind_param once
        $stmt->bind_param("ss",$teacherusername,$teacherpassword);
        // execute query
        $stmt->execute(); 
        // get result and assign variables (prefix with db)
        $stmt->bind_result($dbTeacherForename,$dbTeacherSurname,$dbTeacherUsername,$dbTeacherPassword, $dbActive);

            while($stmt->fetch()) {

      if ($teacherusername == $dbTeacherUsername && $teacherpassword == $dbTeacherPassword) {
   if ($dbActive == 1){

        $loggedIn = true;
}
      }

}
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  1. Editorial Team
    Editorial Team
    2026-06-09T13:28:26+00:00Added an answer on June 9, 2026 at 1:28 pm

    If you’re only returning one row, you don’t need a while loop. bind_result() takes x columns and assigns their values, in order, to the variables you pass in. So, assuming that your result only contains one row with one column, bind_result($dbactive) would be the same as $dbactive = $row['active'] with mysql_*.

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