Question

In one byte i set some bits
|Video | Audio | speaker | mic | Headphone | Led with bits
|1 | 1 | 1 | 3 | 1 | 1
1 byte for all except for mic which has 3 bytes and thus can have 7 combination leaving
the first combination.

#define Video    0x01
#define Audio    0x02
#define Speaker     0x04
#define MicType1  0x08 
#define MicType2  0x10
#define MicType3  0x20
#define MicType4 (0x08 | 0x10) 
#define MicType5 (0x08 | 0x20)
#define MicType6 (0x10 | 0x20)
#define MicType7 ((0x08 | 0x10) | 0x20)
#define HeadPhone 0x40
#define Led    0x80

Now I set the bits

MySpecs[2] |= (1 << 0);
MySpecs[2] |= (1 << 2);

//set mictype6

MySpecs[2] |= (1 << 4);
MySpecs[2] |= (1 << 5);

when I do read like this

 readCamSpecs()
    {
        if(data[0] &  Video)
            printf("device with Video\n");
        else
            printf("device with no Video\n");
        if(data[0] & Audio) 
            printf("device with Audio\n");
        else
            printf("device with no Audio\n");

        if(data[0] & Mictype7)
            printf("device with Mictype7\n");
        if(data[0] & Mictype6)
            printf("device with Mictype6\n");
    }

The values set with single bits, it can find.
But the values set with multiple bits (e.g, MicType5,6,7) it makes error
and displays whatever is the first in check.
What am I doing wrong?

Answer 1

Your & check succeeds even when there’s only one bit set, as the result would still be non-zero.

Try if ( data[0] & Mictype7 == MicType7 ) instead.