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Home/ Questions/Q 575653
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T13:57:50+00:00 2026-05-13T13:57:50+00:00

In Perl before 5.10 there is no state declaration. I’ve come across an example

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In Perl before 5.10 there is no “state” declaration.

I’ve come across an example of creating static variables in these Perls: my $x if 0. The if 0 conditional makes the variable act like a static variable:

use strict; use warnings;
add() for 1..7;

sub add {
    my @arr = () if 0;

    push @arr, '+';
    print @arr, "\n";
}

prints:

+
++
+++
++++
+++++
++++++
+++++++

Is this behaviour consistent in all versions of Perl before 5.10?

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  1. Editorial Team
    Editorial Team
    2026-05-13T13:57:50+00:00Added an answer on May 13, 2026 at 1:57 pm

    I’ve always used scoping braces to create static variables.

    add() for 1..2;       # Append to existing.
    add('foo', 'bar');    # Re-initialize if args are passed.
    add() for 1..2;       # Append to existing.
    {
        my @arr;
        sub add {
            @arr = @_ if @_;
            push @arr, '+';
            print @arr, "\n";
        }
    }
    
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