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Home/ Questions/Q 8282293
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T10:19:24+00:00 2026-06-08T10:19:24+00:00

In this code.. public static TransactionScope CreateTransactionScope(bool createNew = false) { return new TransactionScope(

  • 0

In this code..

public static TransactionScope CreateTransactionScope(bool createNew = false)
{
    return new TransactionScope(
        createNew ? TransactionScopeOption.RequiresNew : TransactionScopeOption.Required,
        new TransactionOptions() { IsolationLevel = IsolationLevel.ReadCommitted });
}

Actually, in this one…

using (TransactionScope rootScope = CreateTransactionScope())
{
    using (TransactionScope nestedOne = CreateTransactionScope())
    { nestedOne.Complete(); }

    using (TransactionScope nestedTwo = CreateTransactionScope(true))
    { nestedTwo.Complete(); }

    // No committing, rollback 'rootScope'.
}

What transactions will be rolled back along with the root one – will it be only nestedOne or both nestedOne and nestedTwo?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T10:19:26+00:00Added an answer on June 8, 2026 at 10:19 am

    nestedOne will join the root scope, so if the root scope will rollback, nestedOne will be roll back as well, but not nestedTwo which is a seperate transaction.

    like you have the “RequireNew” option that seperate the transaction from the enclosing transaction you can have the “Suppress” option that stops the transaction for that scope.

    Take a look at the following list from MSDN that gives a great lesson about transactions behaviour.
    http://msdn.microsoft.com/en-us/library/ms172152(v=vs.90).aspx

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