Question

include_once 'include/connect_db.php';
$query="SELECT tm FROM schedule WHERE val='BT009';";
$result=ejecutar_query($query);

$rows = array();

if ($result && mysql_num_rows($result)) {
    foreach ($result as $row):
        $rows[] = $row['tm'];
        echo $row['tm'];       
    endforeach;
}

I’m sure SQL query should return 1 entry. However, echo outputs ‘Array’. The error message is: Invalid argument supplied for foreach().

Answer 1

Change your for loop:

while($row = mysql_fetch_array($result)) {
    $rows[] = $row['ETA'];
    echo $row['ETA'];
}
print_r($rows); // To double check