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Editorial Team
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Asked: 2026-06-08T20:46:40+00:00

Initially I was working with two query, One was returning Student’s marks, second was

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Initially I was working with two query,
One was returning Student’s marks,
second was returning Grand Total Marks.

Now I decided to Union these two queries but my Grand Total row is appearing at top, which I want at bottom, I tried changing the sequencing of two, but no impact on result. Please suggest, my query is:

SELECT AISECTRESULT_Schemes.SUBNO, 
        AISECTRESULT_Schemes.SUBJECT, 
        AISECTRESULT_Schemes.CE_TotalMarks, 
        AISECTRESULT_ExamMarksData.TotalMarksObt_C, 
        AISECTRESULT_Schemes.TE_TotalMarks, 
        AISECTRESULT_ExamMarksData.TotalMarksObt,
        MAXMARKS, 
        AISECTRESULT_ExamMarksData.OverAllMarks 
  FROM AISECTRESULT_Schemes 
 INNER JOIN AISECTRESULT_ExamMarksData 
    ON AISECTRESULT_Schemes.[EXAMSCHEME ID] = AISECTRESULT_ExamMarksData.EXAMSCHEMEID
 WHERE (AISECTRESULT_ExamMarksData.REGISTRATIONID = '201192145')

UNION

SELECT ''AS SUBNO,
       ''AS SUBJECT,
        SUM(AISECTRESULT_Schemes.CE_TotalMarks)CE_TotalMarks, 
        SUM(AISECTRESULT_ExamMarksData.TotalMarksObt_C)TotalMarksObt_C,
        SUM(AISECTRESULT_Schemes.TE_TotalMarks)TE_TotalMarks, 
        SUM(AISECTRESULT_ExamMarksData.TotalMarksObt)TotalMarksObt,
        SUM(AISECTRESULT_Schemes.MAXMARKS)MAXMARKS,
        SUM(AISECTRESULT_ExamMarksData.OverAllMarks)OverAllMarks
  FROM AISECTRESULT_Schemes
 INNER JOIN AISECTRESULT_ExamMarksData
    ON AISECTRESULT_Schemes.[EXAMSCHEME ID] = AISECTRESULT_ExamMarksData.EXAMSCHEMEID
 WHERE (AISECTRESULT_ExamMarksData.REGISTRATIONID = '201192145')

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1 Answer

  1. Editorial Team

    You need an ORDER BY on your query. This should do it:

    SELECT  SUBNO, 
        SUBJECT, 
        CE_TotalMarks, 
        TotalMarksObt_C, 
        TE_TotalMarks, 
        TotalMarksObt,
        MAXMARKS, 
        OverAllMark
FROM (  SELECT  AISECTRESULT_Schemes.SUBNO, 
                AISECTRESULT_Schemes.SUBJECT, 
                AISECTRESULT_Schemes.CE_TotalMarks, 
                AISECTRESULT_ExamMarksData.TotalMarksObt_C, 
                AISECTRESULT_Schemes.TE_TotalMarks, 
                AISECTRESULT_ExamMarksData.TotalMarksObt,
                MAXMARKS, 
                AISECTRESULT_ExamMarksData.OverAllMarks,
                1 ColOrder
        FROM AISECTRESULT_Schemes 
        INNER JOIN AISECTRESULT_ExamMarksData 
        ON AISECTRESULT_Schemes.[EXAMSCHEME ID] = AISECTRESULT_ExamMarksData.EXAMSCHEMEID
        WHERE AISECTRESULT_ExamMarksData.REGISTRATIONID = '201192145'

        UNION

        SELECT  ''AS SUBNO,''AS SUBJECT,
                SUM(AISECTRESULT_Schemes.CE_TotalMarks)CE_TotalMarks, 
                SUM(AISECTRESULT_ExamMarksData.TotalMarksObt_C)TotalMarksObt_C,
                SUM(AISECTRESULT_Schemes.TE_TotalMarks)TE_TotalMarks, 
                SUM(AISECTRESULT_ExamMarksData.TotalMarksObt)TotalMarksObt,
                SUM(AISECTRESULT_Schemes.MAXMARKS)MAXMARKS,
                SUM(AISECTRESULT_Exa![enter image description here][1]mMarksData.OverAllMarks)OverAllMarks,
                2
        FROM AISECTRESULT_Schemes 
        INNER JOIN AISECTRESULT_ExamMarksData 
        ON AISECTRESULT_Schemes.[EXAMSCHEME ID] = AISECTRESULT_ExamMarksData.EXAMSCHEMEID 
        WHERE AISECTRESULT_ExamMarksData.REGISTRATIONID = '201192145') AS Data
ORDER BY ColOrder
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