Question

int main() {

    vector <int> multiples(1);

    cout << multiples[0];

}

This returns 0 when I want it to be 1. This happens when I initialize the vector with one element, I can access the second element, however:

int main() {

    vector <int> multiples(1, 4);

    cout << multiples[1]; // 4

}

Moreover, when I try to access elements in the vector that do not exist, I get the value of the rightmost element (in this case, 4). But I cannot seem to get the first element however. Can anyone explain why?

Answer 1

This

vector <int> multiples(1);

creates a vector of int with size 1. The single element is value initialized, which for ìnt means zero initialized. So you get a vector with one entry, with value 0. And this one

vector <int> multiples(1, 4);

creates a vector of size 1, this time with value4. If you try to access multiplies[1] you are going beyond the bounds of your size-1 vector, thereby invoking undefined behaviour. It you want to initialize a vector with two elements of values 1 and 4, in C++11 you can do this:

vector <int> multiples{1, 4};