Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8294663
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 8, 20262026-06-08T14:18:02+00:00 2026-06-08T14:18:02+00:00

int main(void) { const char* kung = Foo; delete []kung; } In this piece

  • 0
 int main(void) {
    const char* kung = "Foo";

    delete []kung;
}

In this piece of code, why do I get the following debug assert failed block_type_is_valid ?

Is it because kung pointer is pointing to a constant string in the memory which cannot be de-allocated ?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-08T14:18:03+00:00Added an answer on June 8, 2026 at 2:18 pm

    Because you can’t delete a string literal (which is what kung points to).

    You also can’t delete an automatic-storage string (so it’s not really the literal part):

    char kung[] = "Foo";
    delete []kung;   //still illegal
    

    Only delete[] memory you allocate with new[].

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I had this code: int foo(void){ return 1; } int main(void){ static const int
So...I have the following code: int main(void) { const char *s=hello, world; cout<<&s[7]<<endl; return
int main(void) { std::string foo(foo); } My understanding is that the above code uses
consider the code #include<stdio.h> int main(void) { char* a; scanf(%s,a);//&a and &a[0] give same
int main(void) { char testStr[50] = Hello, world!; char revS[50] = testStr; } I
int main(void) { char *p = hello; char *q = world; *p = *q;
I'm trying to do this: int main(void){ u_int64_t NNUM = 2<<19; u_int64_t list[NNUM], i;
Consider the following program: #include <stdio.h> int main(void) { return 0; } When i
int main(void) { int* p = (int*) malloc(sizeof(int)); int* q = (int*) malloc(sizeof(int)); *p
... int main(void) { int i; for(i=0;i<2;i++){ switch(fork()){ case 0: sleep(1); break; default: sleep(1);

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.