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Home/ Questions/Q 75541
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Asked: May 10, 20262026-05-10T20:31:56+00:00 2026-05-10T20:31:56+00:00

Is it possible to define a spring-managed EJB3 hibernate listener? I have this definition

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Is it possible to define a spring-managed EJB3 hibernate listener?

I have this definition in my persistence.xml:

<properties>      <property name='hibernate.ejb.interceptor'         value='my.class.HibernateAuditInterceptor' />      <property name='hibernate.ejb.event.post-update'         value='my.class.HibernateAuditTrailEventListener' />  </properties> 

But I would like to manage HibernateAuditInterceptor and HibernateAuditTrailEventListener with spring, so I can do some bean injection (ex: session-scoped bean) within these classes. Is this possible?

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  1. 2026-05-10T20:31:57+00:00Added an answer on May 10, 2026 at 8:31 pm

    The problem is that those properties are just strings. Even if you define your SessionFactory as a Spring bean, any properties you pass to it through the hibernateProperties setter are just strings:

    <bean id='mySessionFactory' class='org.springframework.orm.hibernate3.LocalSessionFactoryBean'>     <property name='dataSource'ref='myDataSource'/>     <property name='mappingResources'>         <list>             <value>whatever.hbm.xml</value>         </list>     </property>     <property name='hibernateProperties'>         <value>             hibernate.ejb.interceptor= my.class.HibernateAuditInterceptor         </value>         <value>             hibernate.ejb.event.post-update=my.class.HibernateAuditTrailEventListener         </value>     </property> </bean> 

    So I don’t think you can do that.

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