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Home/ Questions/Q 8345683
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T06:45:39+00:00 2026-06-09T06:45:39+00:00

Is it possible to make the following code work? def zeroTo[N <: Nat]:Sized[List[Int], N]

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Is it possible to make the following code work?

def zeroTo[N <: Nat]:Sized[List[Int], N] = {
  new Sized[List[Int], N](List.iterate(0, toInt[N])(1+)) {
    type A = Int
  }
}

I get a compile error saying “could not find implicit value for parameter toIntN: shapeless.ToInt[N]”.

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  1. Editorial Team
    Editorial Team
    2026-06-09T06:45:40+00:00Added an answer on June 9, 2026 at 6:45 am

    You can just add a context bound:

    def zeroTo[N <: Nat: ToInt]: Sized[List[Int], N] = {
      new Sized[List[Int], N](List.iterate(0, toInt[N])(1+)) {
        type A = Int
      }
    }
    

    Which gives us:

    scala> zeroTo[_6]
    res0: shapeless.Sized[List[Int],shapeless.Nat._6] = List(0, 1, 2, 3, 4, 5)
    

    Note that you can write this more or less equivalently as the following using wrap:

    def zeroTo[N <: Nat: ToInt]: Sized[List[Int], N] =
      Sized.wrap(List.iterate(0, toInt[N])(1+))
    

    Update: Version for Shapeless 2.2.0:

    def zeroTo[N <: Nat: ToInt]: Sized[List[Int], N] = {
      Sized.wrap[List[Int], N]( List.iterate( 0, toInt[N] )( 1+ ) )
    }
    
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