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Editorial Team
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Asked: 2026-06-07T05:37:21+00:00

Is it possible to parse a django template and only render a specific tag

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Is it possible to parse a django template and only render a specific tag ?
This snippet is close to what I’m looking for but it doesn’t return the entire template.
Basically if I have this template as input

<html>
<title>{% block title%}{% endblock %}</title>
<body>
{% block content %}
{% mycustomtag "args" %}
{% endblock content %}
</body>
</html>

and i want to only render mycustomtag this is the output Im looking for

<html>
<title>{% block title%}{% endblock %}</title>
<body>
{% block content %}
<p>Result from mycustomtag</p>
{% endblock content %}
</body>
</html>

Thanks.

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1 Answer

  1. Editorial Team

    If I properly understand your question, then there is a way to do that, using the {% verbatim %} tag. It will be added in Django 1.5, but for now you can use it as your custom tag – here is the source: https://code.djangoproject.com/ticket/16318

    The only drawback here is that you cannot use directly this template, it needs double rendering. If this is what you need – then everything is OK.

    To use it, all you need to do is to enclose the other tags with {% verbatim %} :

    {% load my_custom_tags %}  <-- this is needed to load the 'verbatim' and 'mycustomtag' tags
{% verbatim %}
<html>
<title>{% block title%}{% endblock %}</title>
<body>
{% block content %}
{% endverbatim %}

{% mycustomtag "args" %}

{% verbatim %}
{% endblock content %}
</body>
</html>
{% endverbatim %}

    I’ve made a simple test with this template: 

    @register.simple_tag
def mycustomtag(a):
    return "<p>%s</p>" % a

....

from django.template import loader, Context
print loader.get_template("test.html").render(Context({}))

    This prints the following:

    <html>
<title>{%block title%}{%endblock%}</title>
<body>
{%block content%}

<p>args</p>

{%endblock content%}
</body>
</html>

    Hope this could be helpful.

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