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Home/ Questions/Q 171869
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Asked: May 11, 20262026-05-11T13:03:51+00:00 2026-05-11T13:03:51+00:00

Is there a way to disable caching of serialized object in Java? I have

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Is there a way to disable caching of serialized object in Java?

I have this scenario:

  1. I have an object which is Serializable, I am serializing it, deserializing it, values are OK.
  2. On the same object, I am changing some value, I am serializing it, deserializing it, values are NOT OK, values are same as the first initially loaded.

Seems like the serializator is caching the values, or not?

Thanks

Copied this example from ‘fredrik’ and adopted to my case:

public class SerialDeserial {     public static void main(String[] args) {         try {             ChangingObject obj = new ChangingObject();             obj.foo=1;             // Write it             ObjectOutputStream os = new ObjectOutputStream(new FileOutputStream('test.foo'));             os.writeObject(obj);             os.flush();os.close();              // Read the object             ObjectInputStream is = new ObjectInputStream(new FileInputStream('test.foo'));             ChangingObject objDummy = (ChangingObject)is.readObject();             System.out.println('objDummy.foo is '+objDummy.foo);              // Change it             obj.foo=2;             // Write it             os = new ObjectOutputStream(new FileOutputStream('test.foo'));             os.writeObject(obj);             os.flush();os.close();              // Read the object             is = new ObjectInputStream(new FileInputStream('test.foo'));             objDummy = (ChangingObject)is.readObject();             System.out.println('objDummy.foo is '+objDummy.foo); // this returns '1' insted of '2'           } catch (Exception e) {             e.printStackTrace();         }     } }  class ChangingObject implements Serializable {     public int foo; }   
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1 Answer

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  1. 2026-05-11T13:03:52+00:00Added an answer on May 11, 2026 at 1:03 pm

    ObjectOutputStream.reset.

    You can also write the object with writeUnshared, but that is shallow so referenced objects will still be shared.

    Of course, immutable objects are a win as usual.

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