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Home/ Questions/Q 8200845
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T06:35:34+00:00 2026-06-07T06:35:34+00:00

Is there any way to create a derived column based on the result of

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Is there any way to create a derived column based on the result of an expression in 10g?

Specifically, I have inherited a table which contains both character data and numeric data within a varchar2 field. Obviously, that causes no end of headaches when trying to do joins, as I constantly get “invalid number” errors when Oracle reorders my query which utilizes to_number() on the field. So, what I’d like to do is create a derived column which has a value if the original column’s value is numeric and NULL if it is not and use that in the join rather than the field with mixed types.

Note that I’m attempting to do this in a query, not in a procedure/function.

Is such a thing possible?

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  1. Editorial Team
    Editorial Team
    2026-06-07T06:35:36+00:00Added an answer on June 7, 2026 at 6:35 am

    The closest you can come in 10g is a function-based index. Something like

    CREATE OR REPLACE FUNCTION my_to_number( p_str IN VARCHAR2 )
      RETURN NUMBER
      DETERMINISTIC
    IS
      l_num NUMBER;
    BEGIN
      l_num := to_number( p_str );
      RETURN l_num;
    EXCEPTION
      WHEN OTHERS THEN
        RETURN NULL;
    END;
    
    CREATE INDEX idx_derived_column
        ON table_name( my_to_number( column_name ) );
    

    This generally requires that a function be created and referenced in your query but the function-based index pre-computes the result so you’re not actually calling the function at run-time. If you really want to avoid the function, you could create the index on a CASE statement as well and then reference that same CASE statement in your query but that would seem to complicate the situation, not make it simpler.

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