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Home/ Questions/Q 8253913
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T01:02:31+00:00 2026-06-08T01:02:31+00:00

Is this program OK, or can it be improved (but simply)? How do I

  • 0

Is this program OK, or can it be improved (but simply)? How do I make sure no repeat numbers are entered?

int n;
int array[9];

cout<<"Enter Number Between 9-0 Only"<<endl;
for(int i = 0; i<=10; i++){
    cout<<"Enter Number" <<(i+1)<<endl;
    cin >> n;
    if((n >= 0) && (n <=9)){
       array[i]=n;
     }
        else{
        cout<<"Numbers from 0-9 only\n"<<endl;

        break;
    }

}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T01:02:34+00:00Added an answer on June 8, 2026 at 1:02 am

    (edit) complete, compiling code

    To check if the numbers are used with higher performance, try something like this (using the working code from Jack Radcliffe):

    #include <iostream>
    using namespace std;
    
    int main()
    {
      int n = 0;
      int array[9] = {0};
    
      bool isUsed[10] = {0};
    
      for(int i = 0; i < 9; i++) 
      {
        cout << "Enter Number " << (i + 1) << endl;
        cin >> n;
    
        if((n >= 0) && (n <= 9))
        {
          if (isUsed[n] == false)
          {
            array[i] = n;
            isUsed[n] = true;
          }
    
          else
          {
            cout << "Number has already been used." << endl;
            i--;
          }
        }
    
        else 
        {
          cout << "Numbers from 0-9 only." << endl;
          i--;
        }
      }
    
      return 0;
    }
    

    Optimization isn’t exactly necessary with this simple of code, but it’s this seems to be an exercise of practice, so why not practice optimized code, too?

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