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Home/ Questions/Q 629837
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T19:47:27+00:00 2026-05-13T19:47:27+00:00

I’ve been trying to optimize some extremely performance-critical code (a quick sort algorithm that’s

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I’ve been trying to optimize some extremely performance-critical code (a quick sort algorithm that’s being called millions and millions of times inside a monte carlo simulation) by loop unrolling. Here’s the inner loop I’m trying to speed up:

// Search for elements to swap.
while(myArray[++index1] < pivot) {}
while(pivot < myArray[--index2]) {}

I tried unrolling to something like:

while(true) {
    if(myArray[++index1] < pivot) break;
    if(myArray[++index1] < pivot) break;
    // More unrolling
}


while(true) {
    if(pivot < myArray[--index2]) break;
    if(pivot < myArray[--index2]) break;
    // More unrolling
}

This made absolutely no difference so I changed it back to the more readable form. I’ve had similar experiences other times I’ve tried loop unrolling. Given the quality of branch predictors on modern hardware, when, if ever, is loop unrolling still a useful optimization?

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  1. Editorial Team
    Editorial Team
    2026-05-13T19:47:27+00:00Added an answer on May 13, 2026 at 7:47 pm

    Loop unrolling makes sense if you can break dependency chains. This gives a out of order or super-scalar CPU the possibility to schedule things better and thus run faster.

    A simple example:

    for (int i=0; i<n; i++)
    {
      sum += data[i];
    }
    

    Here the dependency chain of the arguments is very short. If you get a stall because you have a cache-miss on the data-array the cpu cannot do anything but to wait.

    On the other hand this code:

    for (int i=0; i<n-3; i+=4)  // note the n-3 bound for starting i + 0..3
    {
      sum1 += data[i+0];
      sum2 += data[i+1];
      sum3 += data[i+2];
      sum4 += data[i+3];
    }
    sum = sum1 + sum2 + sum3 + sum4;
    // if n%4 != 0, handle final 0..3 elements with a rolled up loop or whatever
    

    could run faster. If you get a cache miss or other stall in one calculation there are still three other dependency chains that don’t depend on the stall. A out of order CPU can execute these in parallel.

    (See Why does mulss take only 3 cycles on Haswell, different from Agner's instruction tables? (Unrolling FP loops with multiple accumulators) for an in-depth look at how register-renaming helps CPUs find that parallelism, and an in depth look at the details for FP dot-product on modern x86-64 CPUs with their throughput vs. latency characteristics for pipelined floating-point SIMD FMA ALUs. Hiding latency of FP addition or FMA is a major benefit to multiple accumulators, since latencies are longer than integer but SIMD throughput is often similar.)

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