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Home/ Questions/Q 8230787
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T17:14:55+00:00 2026-06-07T17:14:55+00:00

I’ve been working with Django in order to make my portfolio and I’ve managed

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I’ve been working with Django in order to make my portfolio and I’ve managed to make a simple page manager. The problem is, it does not work how I want it to work:

  1. I create the page.
  2. It loads the content I gave it.
  3. With jQuery, I load only that content (as formatted HTML).
  4. It shows itself without reloading or moving to another page.

The problem is with the last two steps, I can’t get the view and template to only load one.

Views.py:

def paginas(request, title):
    get_page = Page.objects.all() # I can't think of a way to make a proper filter
    return render_to_response('template.html', {'get_page': get_page}, context_instance=RequestContext(request), mimetype="text/html")

Template.html:

{% if get_page %}
    {% for page in get_page %}
            {{ page.content|safe }}
            <p>Full path is {{ request.get_full_path }} and page id is {{ page.id }}</p>
    {% endfor %}
{% else %}
    <p>Nothing.</p>
{% endif %}

I know I should filter it, but I don’t know how.

I appreciate your help.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T17:14:57+00:00Added an answer on June 7, 2026 at 5:14 pm

    tbh, the django tutorial explains urls, parameters and forms very clear, but here’s the idea:

    url(r'^/someapp/(?P<page_id>\d+)/$', paginas),
    
    
    def paginas(request, **kwargs):
        id = kwargs.pop('page_id')
        page = get_object_or_404(Page, id=id)
        # etcetera
    
    
    class Page(models.Model):
        # regular stuff
        def get_absolute_url(self):
            return "/someapp/%d/" % self.id
    
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