Question

I’ve created a drop down menu which contains 5 choices. When a user selects a choice and presses the submit button, how do I transfer that “selection” to the backend/server in Django?

After that, when the value of the selection reaches the backend, I intend to use the value to create another form. There are 5 forms to choose from (one for each choice) and the type of form that appears will depend on the value of the original selection.

This is what I have so far, but I get the error, “Key ‘selection’ not found in QueryDict: {}”

Here’s the HTML file:

<div id = "f1" style="display:none">
  <form name= "form1" action='/products/{{ action }}/' method='get'>
    <p class="choice-header"> Product: </p>
    <select id = "g1" title="selection" onchange = "showForm()">
      <option value = "0">--</option>
      <option value = "1">Form 1</option>
      <option value = "2">Form 2</option>
      <option value = "3">Form 3</option>
      <option value = "4">Form 4</option>
      <option value = "5">Form 5</option>
    </select>
    <div id= "b1" style="display:none">
      <input class="button" type=submit value="{{ button }}">
    </div>
  </form>
</div>

Here’s the Django views.py file

def new2(request):
  form_no = request.GET["selection"]

  if form_no == 1:
    form_to = Form1()
  c = RequestContext(request, {
    'action': 'add/2',
    'button': 'Add', 
    'form': form_to,
  })
  return render_to_response('links/add.html', c)

Thanks for the help!

Answer 1

This isn’t really a Django issue. You just haven’t given your select element a name attribute.

<select id="g1" name="selection">