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Home/ Questions/Q 8361345
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T11:40:33+00:00 2026-06-09T11:40:33+00:00

I’ve searched around a bit, but haven’t found a good answer yet on how

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I’ve searched around a bit, but haven’t found a good answer yet on how to filter out any entries into a map that have a value of None. Say I have a map like this:

val map = Map[String, Option[Int]]("one" -> Some(1), 
                                   "two" -> Some(2), 
                                   "three" -> None)

I’d like to end up returning a map with just the ("one", Some(1)) and ("two", Some(2)) pair. I understand that this is done with flatten when you have a list, but I’m not sure how to achieve the effect on a map without splitting it up into keys and values, and then trying to rejoin them.

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  1. Editorial Team
    Editorial Team
    2026-06-09T11:40:35+00:00Added an answer on June 9, 2026 at 11:40 am

    Like every collection type in the scala.collection namespace a Map has the filter method defined and Optionhas the isDefined method, which is true for Some and false for None. You can filter out the Nonevalues by combining these two:

    scala> map.filter(_._2.isDefined)
    res4: scala.collection.immutable.Map[String,Option[Int]] = Map(one -> Some(1), two -> Some(2))
    
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