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Home/ Questions/Q 8334505
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T03:22:41+00:00 2026-06-09T03:22:41+00:00

I’ve seen a lot of ObjC code which do: obj = [[SomeObject alloc] init];

  • 0

I’ve seen a lot of ObjC code which do:

obj = [[SomeObject alloc] init];
if (obj) {
/// ...
}

but as I understood it, the value inside () is a boolean, and 0 indicates FALSE 1 indicates TRUE(there is another case in other language that 0 is true and 1 is false), and if a pointer does not point to anything, it is set to NULL(nil), which is #defined to be 0, so I wonder is it better if I do:

if (obj != nil) {
/// ...
}

as it IS checking if the obj is nil or not, no matter what value nil is, so it does not rely on that nil (or NULL) happen to be defined as 0?

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  1. Editorial Team
    Editorial Team
    2026-06-09T03:22:43+00:00Added an answer on June 9, 2026 at 3:22 am

    edit:
    after testing a bit, I have determined that modern compilers will actually create the same machine code for both cases;

    orig post:

    It is (negligibly, perhaps) more efficient to use

    if(obj) {
    

    since you do not need to create the intermediary boolean value (by evaluating the comparison expression). I’m not sure which “other language” you are referring to regarding the non-zero being FALSE; the closest thing I can think of is c programs returning 0 for “success” and anything else for “error”. Every modern language I have ever worked with uses 0 as FALSE and any non zero value for TRUE.

    In Objective-C, nil is literally 0 (treated like a pointer). It is not just a pointer to zero, it is zero as a pointer. It is therefore reliably equivalent to FALSE (or, in our nomenclature “NO”).

    edit
    after testing a bit, I have determined that modern compilers will actually create the same machine code for both cases; probably because nil is essentiall typedef’d to 0, so it knows the two styles of checking are both saying “if this pointer is non-zero”.

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