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Home/ Questions/Q 8173303
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T22:05:56+00:00 2026-06-06T22:05:56+00:00

I’ve stumbled upon something that I’m guessing is a bug in Data.Map , but

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I’ve stumbled upon something that I’m guessing is a bug in Data.Map, but which is also quite possibly a bug in my Haskell knowledge. Hoping somebody can clarify which it is 🙂

Please reference this gist. I’m serializing a circular linked list structure to a bytestream. For any given node, of the form:

data Node = Node
  { val  :: Word8
  , next :: Node
  }

I expect it to be serialized as a pair of bytes: the first byte representing val, and the second byte representing the offset in the bytestream where next can be located. For example, I expect:

let n0 = Node 0 n1
    n1 = Node 1 n0

to be serialized as [0, 1, 1, 0]. No big deal.

The slightly tricky part here is that I’m exploiting the MonadFix instance for RWST to “tie the knot” of bytestream offsets: I maintain a map from nodes to offsets, populating the map during serialization, but also referencing entries in the map that don’t necessarily exist yet until serialization is complete.

This works great when the map implementation is Data.HashMap.Lazy (from unordered-containers). However, when the implementation is the usual Data.Map (from containers), the program stack overflows — no pun intended — with Map trying infinitely to compare the two nodes using (==).

So my question is: is this a bug in Data.Map, or are my assumptions about how these structures should behave in the presence of mfix flawed?

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  1. Editorial Team
    Editorial Team
    2026-06-06T22:05:58+00:00Added an answer on June 6, 2026 at 10:05 pm

    Your Ord instance doesn’t work:

    instance Ord Node where -- for use in Data.Map
      Node a _ < Node b _ = a < b
    

    For a working Ord instance, you must define compare or (<=). If you only define (<), any call to compare or (<=) will loop infinitely since both have default implementations in terms of each other. Also the other members of Ord are defined in terms of compare, so nothing except (<) will work.

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