Question

JS:

$(function(){
 chainAnim('.section','slow','1')  });
 function chainAnim(e,s,o) {
        var $fade = $(e);
        var code = "console.log('Done.');";
        $fade.each(function(){
   code = "$('#"+$(this).attr('id')+"').fadeTo('"+s+"','"+o+"',function(){"+code+"});";
        });
        eval(code);
}

HTML:

 <div id="wrapper">
  <div class="section" id="section-1">Section 1</div>
  <div class="section" id="section-2">Section 2</div>
  <div class="section" id="section-3">Section 3</div>
  <div class="section" id="section-4">Section 4</div>
 </div>

When animating,section 4 is animated in first. How can I reverse this?

Answer 1

This should do what you want, but I got rid of your eval() code. Not sure why you were taking that approach.

Example: http://jsfiddle.net/wqWE5/

I also changed the second argument from "slow" to 800 so it could be used in the .delay().

The duration you pass multiplied by the current index of the .each() will make the animation happen in sequence.

$(function(){
     chainAnim('.section',800,'1');
});

function chainAnim(e,s,o) {
        var $fade = $(e);
        var code = function() {console.log('Done.');};
        $fade.each(function( i ){
            $(this).delay(i * s).fadeTo(s,o,code);
        });
}