Question

Let me explain this. I have a table where I have two important fields I need :
The first one is a double, and the second one is a date.

I would like to make a requests that groups entries by YYYY-MM-DD, and adds each field of the double by group.

For example, I have two entries the same day :

   |   amount    |    date
1  |    100      | 2010-01-01
2  |    200      | 2010-01-01

What I need is :

1  |     300     | 2010-01-01

Is that possible ? For the moment here is my request :

 SELECT DISTINCT ON (d) amount, to_char(datecreation, 'YYYY-MM-DD') d
   FROM mytable
  GROUP BY d, amount
  ORDER BY d ASC;

What I get is :

1  | 100   | 2010-01-01

It doesn’t add the grouped amounts.

Answer 1

select sum(amount), date from mytable group by date order by sum(amount) ASC;

If your dates have a time part, then

select sum(amount), to_char(date, 'YYYY-MM-DD') from mytable group by to_char(date, 'YYYY-MM-DD') order by sum(amount) ASC;