Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8337817
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 9, 20262026-06-09T04:24:11+00:00 2026-06-09T04:24:11+00:00

Let us say I have a double for loop. /*Just a double for loop

  • 0

Let us say I have a double for loop.

/*Just a double for loop
*/    
for(int i = 0; i<IMAX; i++){
 for(int j = 0; j<JMAX; j++){
   count++;
   recover_loop_indices(count,IMAX,JMAX); /*this is not real world code.Just to illustrate what I mean*/
 }
}

My question is precisely, given count, IMAX and JMAX, is it possible to recover the unique loop indices, i and j?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-09T04:24:12+00:00Added an answer on June 9, 2026 at 4:24 am

    Yes, based on count:

    i = floor(count / JMAX);
    j = count % JMAX;
    

    You don’t need IMAX at all. In fact, this is often how one can reconstruct an image from a serial stream of pixels, given only the width of the stream.

    Edit:

    I am assuming you want to recover the values of i and j before the count++. To recover it after the count++, use (count-1).

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Let's say we have this kind of loop (pseudocode) double d = 0.0 for
Let's say I have interface IMatrix { double this[int r, int c] { get;
Let’s say I have double length that can be either a real length or
Let's say I have two maps: typedef int Id; std::map<Id, std::string> idToStringMap; std::map<Id, double>
Let's say I have the following code snippet: int i; double value; for(i =
Let's say I have this class: class Zoo { protected String bearName; protected Double
Let say I have abstract class called: Tenant and Customer. The tenant in this
Let say i have some words AB, AAB, AA. AB is not a prefix
Let's say I have a number (e.g. double) and transform it using some format
Let's say I have the following class: class ABC { private int myInt =

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.