Question

Let’s define this struct:

struct MyStruct {
    int firstInt;
    int secondInt;
    char * firstString;
    char * secondString;
};

I’m trying to initialize a struct like this:

MyStruct s = {4, 5, {'a', 'b', 'c'}, "abc"};

But it’s not working. Is there any way to do it? (the firstString is required not to have ‘\0’ at the end)

Answer 1

Since your requirement is to not have a null terminator at the end, you have to use an array for firstString:

struct MyStruct {
    int firstInt;
    int secondInt;
    char firstString[3];
    char * secondString;
};

Then you can initialize it like this:

MyStruct s = {4, 5, {'a', 'b', 'c'}, "abc"};

You cannot initialize a char* with {'a', 'b', 'c'} because you have to provide storage for the characters, a char* is only able to point at something. "abc" happens to be a constant string literal which is stored in read only memory, so you are able to make the char* point at that.

Also, in C++, "abc" is a constant which cannot me modified, so you should change char * secondString; to const char * secondString;.