Question

let’s say I have such weird code:

var weirdo = {};
var ids = [10, 30, 11, 1, 4, 2];
var producers = ['Ford','Rover','BMW','Fiat','Renault','Mitsubishi'];
var n = producers.length;
for(var i=0; i<n; i++) {
    weirdo[ids[i]] = producers[i];
}
// unknown code ???

How to sort weirdo by values? It’s not array and no, I can’t sort producers before filling weirdo.

Any ideas?

Oh, and relation id <=> producer is VERY IMPORANT!

Answer 1

You can use an array of objects:

var items = [
  {id:10, producer:'Ford'},
  {id:30, producer:'Rover'},
  {id:11, producer:'BMW'},
  {id:1, producer:'Fiat'},
  {id:4, producer:'Renault'},
  {id:2, producer:'Mitsubishi'},
]

// or, starting from your two arrays:
var items = [];
for (var i=0; i<ids.length && i<producers.length; i++)
    items[i] = {id:ids[i], producer:producers[i]};

Then you can sort that array by id:

items.sort(function(a, b){ return a.id-b.id; });

…and iterate it with a for-loop.

---

Another solution would be an iterator array, to loop over an id<->producer object (weirdo) in the correct order:

var weirdo = {"10":"Ford","30":"Rover",...};
var ids = Object.keys(weirdo); // if not already built somewhere

ids.sort(function(a,b){return a-b;}); // sort numeric
// loop:
for (var i=0; i<ids.length; i++) {
    var id=ids[i], producer=weirdo[id];
    ...
}