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Home/ Questions/Q 8176433
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T23:10:33+00:00 2026-06-06T23:10:33+00:00

Let’s say I have two arrays in my javascript: var content = [string1, string2,

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Let’s say I have two arrays in my javascript:

var content = ["string1", "string2", "string3", "string4"],
    milliseconds = [500, 1500, 1000, 500];

I want each element of content array to be displayed in console one by one with intervals from milliseconds array in a way that string1 is displayed after 500 milliseconds, string2 after 1500 (from the displaying of string1) and so on.

I’m a total beginner, I tried stuff like:

for (var i = 0; i < content.length - 1; i++) {
    setTimeout(function() {
        console.log(content[i]);
    }, milliseconds[i]);
};

But it displays only the last string four times, and it looks like setTimeout methods all start at the same time, not one after another. Is there a way to get the effect I want?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T23:10:37+00:00Added an answer on June 6, 2026 at 11:10 pm

    First of all, the setTimeouts all seem to start at the same time because you’re calling them at the same time. JavaScript doesn’t block – it doesn’t wait for the setTimeout callback to actually fire, it just keeps going. That’s why, since you were using a loop, all of the callbacks were getting scheduled more or less at once.

    The second issue, that all of the console.logs seem to print the same thing, is because of the same loop issue. Since the loop finishes way before any of the callbacks complete, the value of i is set to the last index of the loop. Then, when the callback occurs, guess what i is equal to?

    One technique would be to just keep a running index of the current item.

    // Don't pollute the global namespace
    (function() {
        // Keep the index around
        var i = 0;
    
        // Setup the callback
        var callback = function() {
            console.log(content[i]);
    
            // Stop whenever there's nothing left to log
            if (i < content.length) {
                // Chain the next timeout, using the next string,
                // with the next wait period, using the callback
                i += 1;
                setTimeout(callback, milliseconds[i]);
            }
        };
    
        // Start the first setTimeout
        setTimeout(callback, milliseconds[i]);
    })();
    
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