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Home/ Questions/Q 8194961
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T04:58:48+00:00 2026-06-07T04:58:48+00:00

Let’s say I’m working on a static library foo.a , which makes use of

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Let’s say I’m working on a static library foo.a, which makes use of a function in bar.so.

How do I build this library in such a way that anyone who uses foo.a in their project doesn’t have to explicitly link against bar.so?

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  1. Editorial Team
    Editorial Team
    2026-06-07T04:58:49+00:00Added an answer on June 7, 2026 at 4:58 am

    What you can do in libfoo.a is make a call to dlopen to dynamically link libbar.so. Then, use dlsym to locate the function you want to use.

    typedef void (*BarFunctionType) (const char *);
    FunctionType barFunction;
    
    void initialize_foo_lib () {
        void *h = dlopen("libbar.so", RTLD_LAZY);
        BarFunctionType barFunction = (BarFunctionType) dlsym(h, "barFunction");
        // Note scary looking cast to get your function pointer.
        //... rest of code can call barFunction now
    }
    

    libbar.so should be a C library, or the function should be extern "C" if a C++ library, for you to find the function name properly. Otherwise you will need to mangle the name to find the function with dlsym. You can use objdump -T on the library to check if the names in the library are mangled.

    Realize there is still a dependency on libbar.so, but it is baked into your static library. So the user of libfoo.a does not have to add -lbar to the link line when they link in -lfoo.

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