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Home/ Questions/Q 8303551
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T17:34:31+00:00 2026-06-08T17:34:31+00:00

Let’s start with an example. $array[‘0’] is equal to value1. $array[‘1’] is equal to

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Let’s start with an example.
$array[‘0’] is equal to value1. $array[‘1’] is equal to value2. $array[‘3’] is equal to value1.
I need to write a function that checks if anything but a certain set of strings exists in an array.

If I allowed “value1” and “value2” to exist in an array, and I gave the function the array above, it would return true.

If I fed the function $array[‘0’] = ‘value3’ $array[‘1’] = ‘value2’, the function would return false because the array contains “value3” and only “value1” and “value2” are allowed in this example.
Does a built-in PHP function that does this exist? If not, how would I go about writing it?

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  1. Editorial Team
    Editorial Team
    2026-06-08T17:34:32+00:00Added an answer on June 8, 2026 at 5:34 pm

    This function will do what you’re looking for:

    function anything_but( $input_array, $values) {
        return count( array_diff( array_unique( $input_array), $values)) == 0;
    }
    

    It simply creates a unique $input_array, and computes the difference between that array and the $values array. If there a no elements in that difference, then both arrays had the same elements, and the function will return true. If not, it will have one or more elements, which makes the function return false.

    You can see it working in the demo.

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