Question

My code is returning an object and not what I expected to see. When I output the output in console, I get object but all the data is there. What is supposed to happen, is that the id is passed to actionrow and this does the ajax call to the db. The object is being output from console.log(datarow); in the code.

I am using jqxWidgets for grid and data

// action row.
$("#actionrowbutton").bind('click', function () {
    var selectedrowindex = $("#jqxgrid").jqxGrid('getselectedrowindex');
    var datarow = $("#jqxgrid").jqxGrid('getrowdata', selectedrowindex);
    var rowscount = $("#jqxgrid").jqxGrid('getdatainformation').rowscount;

    if (selectedrowindex >= 0 && selectedrowindex < rowscount) {
        var rows = $('#jqxgrid').jqxGrid('getrows', selectedrowindex);
        var id = $("#jqxgrid").jqxGrid('getrowid', selectedrowindex);
        //var service = datarow;
        console.log(datarow);

        $("#jqxgrid").jqxGrid('actionrow', id);

        //Open action dialog window
        $( "#actionWindow" ).dialog({
          //title: 'action error',
          resizable: false,
          modal: true,
          position: ['center', 'center'],
          buttons: {
             "Ok": function() {
                $(this).dialog("close");

                $('#jqxgrid').jqxGrid('refreshdata');
              },
              Cancel: function() {
                $( this ).dialog( "close" );

                //$('#jqxgrid').jqxGrid('refreshdata');
              }
         }
       });
    }
});

actionrow: function (actrowid) {
    // synchronize with the server - send action command
    var data = "action=true&id=" + actrowid;
    $.ajax({
        dataType: 'json',
        url: 'data.php',
        data: data,
        success: function (data, status, xhr) {
            // action command is executed.
        }
    });                         
}

Answer 1

After looking at your code, I am left with a question.
What is “actionrow”, is it a function or a method of jqxgrid object? If it isn’t it should be written like so:

function actionrow(actrowid) {
    // synchronize with the server - send action command
    var data = "action=true&id=" + actrowid;
    $.ajax({
        dataType: 'json',
        url: 'data.php',
        data: data,
        success: function (data, status, xhr) {
        // action command is executed.
        }
    });                         
}

And called like so in your if statement.

actionrow(id); //not $("#jqxgrid").jqxGrid('actionrow', id);