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Home/ Questions/Q 8301145
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T16:50:06+00:00 2026-06-08T16:50:06+00:00

My custom defined protocol (phpfile) lets me open php-files in an editor through the

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My custom defined protocol (phpfile) lets me open php-files in an editor through the browser. The only problem is, it gives the full url, that is different in each browser, i’ve seen:

  • phpfile:/[file]
  • phpfile:/[file]/
  • phpfile://[file]/
  • phpfile://[file]

All these need to be converted to just [file]. The problem is that I get a syntax error. What is the correct syntax?

set var=%1
if("%var:~0,9%"=="phpfile:/")
{
    set url = %var:~9% 
}
else
{
    set url = %var:~10%
}

if(%var:-1,1% == "/")
{
    url = %url:~0,-1%   
}
START "" "C:\Program Files (x86)\NuSphere\PhpED\7.0\phped.exe" url

=== Edit ===
I now have the following, but it is adding “” at the end of the url

SETLOCAL enabledelayedexpansion

set var=%1

if %var:~0,9%=="phpfile:/" (
    set url = %var:~9% 
) else (
    set url = %var:~10%
)

if "%var:~-1%"=="\" (
    set url = %url:~0,-1%"
)
if "%var:~-1%"=="/" (
    set url = %url:~0,-1%"
)

START "" "C:\Program Files (x86)\NuSphere\PhpED\7.0\phped.exe" %url:"=%
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T16:50:08+00:00Added an answer on June 8, 2026 at 4:50 pm

    There were quite a few problems in your code, this should fix things:

    set var="%1"
    if %var:~0,9%=="phpfile:/" (
        set url="%var:~9%"
    ) else (
       set url="%var:~10%"
    )
    
    if "%var:-1,1%"=="/" (
        set url="%url:~0,-1%"
    )
    START "" "C:\Program Files (x86)\NuSphere\PhpED\7.0\phped.exe" url
    

    You can check the syntax of batch file commands using help <command>. IF statements don’t use curly braces, or require round brackets around the conditional statement.

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