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Home/ Questions/Q 979541
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T04:14:07+00:00 2026-05-16T04:14:07+00:00

My html file: <script> $(document).ready(function() { $.ajax({ type: POST, url: search.php, data: id=1, datatype:

  • 0

My html file:

    <script>
    $(document).ready(function() {  
        $.ajax({
            type: "POST",
            url: "search.php",
            data: "id=1",
            datatype: "json",
            success: function(msg){
                $('.result1').html(msg["name"]);
            }
        });  
    })
    </script>   

    <span class="result1"></span>

My php file:

    <?
    $a["name"] = 'john';
    echo json_encode($a);
    ?>

Why the name John doesn’t appear in class result1? Why? Please help me, I am going insane.

edit: Is it possible to make bounty right now?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T04:14:08+00:00Added an answer on May 16, 2026 at 4:14 am

    The dataType parameter has a capital T. It works if you correct this.

    Currently it is (by default) trying to guess the response format based on the mime-type, so probably defaulting to html – debugging in firebug you can see that the msg argument of the success callback is a string containing the JSON.

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