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Home/ Questions/Q 8250673
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T23:58:24+00:00 2026-06-07T23:58:24+00:00

My regex returns a blank value when the second value is matched in an

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My regex returns a blank value when the second value is matched in an OR statement, I want it to ignore the first match if the second one is found

preg_match('/>\s+(?:<input type="submit" value="(.*?)" \/>|<p class="no">(.*?)<\/p>)\s+<\/form>/', $string, $matches);

If first item is matched:

Array
(
    [0] => <input type="submit" value="Go" />
    [1] => Go
)

If second item is matched:

Array
(
    [0] => <p class="no">Value</p>
    [1] => 
    [2] => Value
)

How can I get it to return the second items value in [1] and not [2] ?

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  1. Editorial Team
    Editorial Team
    2026-06-07T23:58:26+00:00Added an answer on June 7, 2026 at 11:58 pm

    Instead of using (?: to start the options, use (?| [docs]

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