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Home/ Questions/Q 4616912
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T02:03:00+00:00 2026-05-22T02:03:00+00:00

My result set seems fine except I’m getting additional duplicate results which I want

  • 0

My result set seems fine except I’m getting additional duplicate results which I want to avoid, here is that case:

I’m using two tables :

order

id|companyname|routeid|orderdate
1 |company1   | 23dsa | 
2 |company1   | 23dsa | 2011-04-28
3 |company1   | 23dsa | 2011-04-05
4 |company2   | 24gcc | 2011-22-05

vehicle

id| vehiclename | routeid
1 | van1        | 23dsa 
2 | van2        | 24gcc 

This is my query 1 :

select t1.companyname, max(t1.orderdate) as orderdate
from order t1, vehicle t2 where t1.routeid=t2.routeid
group by t1.companyname, t1.orderdate
order by t1.id

This is query 2 :

 select t1.companyname, max(t1.orderdate) as orderdate
    from order t1, vehicle t2 where t1.routeid=t2.routeid
    group by t1.companyname, t1.orderdate having count(1) = 1
    order by t1.id

This is my result :

companyname | orderdate
company1    |  
company1    | 2011-04-28
company1    | 2011-04-05
company2    | 2011-22-05

I’d like it to be like this :

companyname | orderdate
company1    | 2011-04-28
company2    | 2011-22-05

I was missing is not null :

select t1.companyname, max(t1.orderdate) as orderdate
    from order t1, vehicle t2 where t1.orderdate is not null and t1.routeid=t2.routeid
    group by t1.companyname, t1.orderdate
    order by t1.id
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T02:03:01+00:00Added an answer on May 22, 2026 at 2:03 am

    What about:

    SELECT
        companyname, MAX(orderdate) AS orderdate
    FROM
        `order`
    GROUP BY
        companyname
    ORDER BY
        id
    

    And if you need that vehicle stuff in there:

    SELECT
        companyname, MAX(orderdate) AS orderdate
    FROM
        `order` o, vehicle v
    WHERE
        o.routeid=v.routeid
    GROUP BY
        companyname
    ORDER BY
        o.id
    
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